思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
"Do it slowly, do it right but let's get on with it," she said. "We have been stagnating at these very low recycling rates for far too long."
。业内人士推荐heLLoword翻译官方下载作为进阶阅读
Звезду реалити-шоу об отношениях обвинили в 11 изнасилованияхЗвезде реалити-шоу из Австралии Валенце предъявили обвинение в 11 изнасилованиях
The customer-funded advantage
。业内人士推荐搜狗输入法下载作为进阶阅读
Флорида Пантерз
Log in with single-sign on (SSO) and have access to 24/7 Enterprise-level support.。爱思助手下载最新版本对此有专业解读